The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 18 meters so the equation becomes: 2w + 2h = 18.

Putting these two equations together and solving for width (w):

2w + 2h = 18
w + h = \( \frac{18}{2} \)
w + h = 9
w = 9 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 9 - 2w
3w = 9
w = \( \frac{9}{3} \)
w = 3

Since h = 2w that makes h = (2 x 3) = 6 and the area = h x w = 3 x 6 = 18 m²

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (4 + 5) ÷ 2 x 3 - 2²
P: 3 + (9) ÷ 2 x 3 - 2²
E: 3 + 9 ÷ 2 x 3 - 4
MD: 3 + \( \frac{9}{2} \) x 3 - 4
MD: 3 + \( \frac{27}{2} \) - 4
AS: \( \frac{6}{2} \) + \( \frac{27}{2} \) - 4
AS: \( \frac{33}{2} \) - 4
AS: \( \frac{33 - 8}{2} \)
\( \frac{25}{2} \)
12\(\frac{1}{2}\)

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{9}{25}} \)
\( \frac{\sqrt{9}}{\sqrt{25}} \)
\( \frac{\sqrt{3^2}}{\sqrt{5^2}} \)
\(\frac{3}{5}\)

By buying two shirts, Roger will save $48 x \( \frac{45}{100} \) = \( \frac{$48 x 45}{100} \) = \( \frac{$2160}{100} \) = $21.60 on the second shirt.

So, his total cost will be
$48.00 + ($48.00 - $21.60)
$48.00 + $26.40
$74.40

By buying two shirts, Frank will save $25 x \( \frac{40}{100} \) = \( \frac{$25 x 40}{100} \) = \( \frac{$1000}{100} \) = $10.00 on the second shirt.