ASVAB Arithmetic Reasoning Practice Test 78299 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?

62% Answer Correctly
2\(\frac{1}{2}\) cups
1\(\frac{3}{4}\) cups
1\(\frac{5}{8}\) cups
2\(\frac{3}{4}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{4}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{26}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{22}{8} \) cups
2\(\frac{3}{4}\) cups


2

Convert c-2 to remove the negative exponent.

67% Answer Correctly
\( \frac{-1}{-2c^{2}} \)
\( \frac{-2}{c} \)
\( \frac{1}{c^2} \)
\( \frac{-1}{-2c} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

greatest common factor

least common factor

least common multiple

absolute value


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


4

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({a \over 5} \)

\({7 \over 5} \)

\({2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


5

What is 7\( \sqrt{3} \) x 4\( \sqrt{8} \)?

41% Answer Correctly
56\( \sqrt{6} \)
11\( \sqrt{3} \)
28\( \sqrt{11} \)
11\( \sqrt{24} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

7\( \sqrt{3} \) x 4\( \sqrt{8} \)
(7 x 4)\( \sqrt{3 \times 8} \)
28\( \sqrt{24} \)

Now we need to simplify the radical:

28\( \sqrt{24} \)
28\( \sqrt{6 \times 4} \)
28\( \sqrt{6 \times 2^2} \)
(28)(2)\( \sqrt{6} \)
56\( \sqrt{6} \)