ASVAB Arithmetic Reasoning Practice Test 7839 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

4! = ?

85% Answer Correctly

4 x 3

5 x 4 x 3 x 2 x 1

3 x 2 x 1

4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


2

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

PEDMAS

commutative

distributive

associative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


3

What is \( 4 \)\( \sqrt{28} \) - \( 7 \)\( \sqrt{7} \)

39% Answer Correctly
\( \sqrt{7} \)
-3\( \sqrt{28} \)
28\( \sqrt{4} \)
28\( \sqrt{196} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{28} \) - 7\( \sqrt{7} \)
4\( \sqrt{4 \times 7} \) - 7\( \sqrt{7} \)
4\( \sqrt{2^2 \times 7} \) - 7\( \sqrt{7} \)
(4)(2)\( \sqrt{7} \) - 7\( \sqrt{7} \)
8\( \sqrt{7} \) - 7\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

8\( \sqrt{7} \) - 7\( \sqrt{7} \)
(8 - 7)\( \sqrt{7} \)
\( \sqrt{7} \)


4

What is 6c2 + 5c2?

66% Answer Correctly
11c4
c2
11c2
-c-2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

6c2 + 5c2
(6 + 5)c2
11c2


5

In a class of 19 students, 8 are taking German and 8 are taking Spanish. Of the students studying German or Spanish, 5 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
10
19
8
12

Solution

The number of students taking German or Spanish is 8 + 8 = 16. Of that group of 16, 5 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 16 - 5 = 11 who are taking at least one language. 19 - 11 = 8 students who are not taking either language.