| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
Simplify \( \frac{16}{48} \).
| \( \frac{1}{4} \) | |
| \( \frac{3}{10} \) | |
| \( \frac{4}{15} \) | |
| \( \frac{1}{3} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 16 are [1, 2, 4, 8, 16] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 5 factors [1, 2, 4, 8, 16] making 16 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{16}{48} \) = \( \frac{\frac{16}{16}}{\frac{48}{16}} \) = \( \frac{1}{3} \)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for division |
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commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
Solve 4 + (3 + 4) ÷ 2 x 4 - 22
| 1\(\frac{1}{6}\) | |
| \(\frac{2}{9}\) | |
| \(\frac{1}{3}\) | |
| 14 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (3 + 4) ÷ 2 x 4 - 22
P: 4 + (7) ÷ 2 x 4 - 22
E: 4 + 7 ÷ 2 x 4 - 4
MD: 4 + \( \frac{7}{2} \) x 4 - 4
MD: 4 + \( \frac{28}{2} \) - 4
AS: \( \frac{8}{2} \) + \( \frac{28}{2} \) - 4
AS: \( \frac{36}{2} \) - 4
AS: \( \frac{36 - 8}{2} \)
\( \frac{28}{2} \)
14
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common factor |
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absolute value |
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least common multiple |
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greatest common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
What is \( \frac{1}{8} \) ÷ \( \frac{1}{8} \)?
| \(\frac{4}{35}\) | |
| \(\frac{4}{15}\) | |
| 8 | |
| 1 |
To divide fractions, invert the second fraction and then multiply:
\( \frac{1}{8} \) ÷ \( \frac{1}{8} \) = \( \frac{1}{8} \) x \( \frac{8}{1} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{8} \) x \( \frac{8}{1} \) = \( \frac{1 x 8}{8 x 1} \) = \( \frac{8}{8} \) = 1