Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{90}{8} \) = 11\(\frac{1}{4}\)

So, it will take 11 full vans and one partially full van to transport the entire team making a total of 12 vans.

Jennifer scored 90% on the test meaning she earned 90% of the possible points on the test. There were 150 possible points on the test so she earned 150 x 0.9 = 135 points. Each question is worth 3 points so she got \( \frac{135}{3} \) = 45 questions right.

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{55}{100} \) = \( \frac{55 x 25}{100} \) = \( \frac{1375}{100} \) = 13 shots

The center makes 50% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{13}{\frac{50}{100}} \) = 13 x \( \frac{100}{50} \) = \( \frac{13 x 100}{50} \) = \( \frac{1300}{50} \) = 26 shots

to make the same number of shots as the guard and thus score the same number of points.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 3}{3 x 3} \) - \( \frac{3 x 1}{9 x 1} \)

\( \frac{12}{9} \) - \( \frac{3}{9} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{12 - 3}{9} \) = \( \frac{9}{9} \) = 1

There are 4 5-passenger taxis available so that's 4 x 5 = 20 total seats. There are 25 people needing transportation leaving 25 - 20 = 5 who will have to find other transportation.