| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
What is \( \frac{4}{9} \) x \( \frac{1}{6} \)?
| \(\frac{4}{21}\) | |
| \(\frac{1}{64}\) | |
| \(\frac{2}{27}\) | |
| \(\frac{2}{3}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{9} \) x \( \frac{1}{6} \) = \( \frac{4 x 1}{9 x 6} \) = \( \frac{4}{54} \) = \(\frac{2}{27}\)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 45% off." If Monty buys two shirts, each with a regular price of $30, how much will he pay for both shirts?
| $43.50 | |
| $45.00 | |
| $46.50 | |
| $13.50 |
By buying two shirts, Monty will save $30 x \( \frac{45}{100} \) = \( \frac{$30 x 45}{100} \) = \( \frac{$1350}{100} \) = $13.50 on the second shirt.
So, his total cost will be
$30.00 + ($30.00 - $13.50)
$30.00 + $16.50
$46.50
Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 10 small cakes per hour. The kitchen is available for 4 hours and 29 large cakes and 480 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 14 | |
| 7 | |
| 11 | |
| 5 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 4 x 4 = 16 large cakes during that time. 29 large cakes are needed for the party so \( \frac{29}{16} \) = 1\(\frac{13}{16}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 10 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 10 x 4 = 40 small cakes during that time. 480 small cakes are needed for the party so \( \frac{480}{40} \) = 12 cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 2 + 12 = 14 cooks.
| 0.8 | |
| 2.7 | |
| 6.0 | |
| 1 |
1
What is (x3)3?
| x0 | |
| x9 | |
| x6 | |
| 3x3 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x3)3