ASVAB Arithmetic Reasoning Practice Test 790295 Results

Your Results Global Average
Questions 5 5
Correct 0 3.62
Score 0% 72%

Review

1

Which of the following is a mixed number?

82% Answer Correctly

\({5 \over 7} \)

\({a \over 5} \)

\({7 \over 5} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

distributive

associative

PEDMAS

commutative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


3

How many 14-passenger vans will it take to drive all 77 members of the football team to an away game?

81% Answer Correctly
6 vans
9 vans
4 vans
8 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{77}{14} \) = 5\(\frac{1}{2}\)

So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.


4

What is \( \frac{3}{7} \) x \( \frac{4}{5} \)?

72% Answer Correctly
2\(\frac{2}{5}\)
\(\frac{12}{35}\)
\(\frac{1}{27}\)
\(\frac{1}{9}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{7} \) x \( \frac{4}{5} \) = \( \frac{3 x 4}{7 x 5} \) = \( \frac{12}{35} \) = \(\frac{12}{35}\)


5

What is z2 + 8z2?

66% Answer Correctly
-7z2
9z4
7z-2
9z2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1z2 + 8z2
(1 + 8)z2
9z2