| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
How many hours does it take a car to travel 70 miles at an average speed of 70 miles per hour?
| 9 hours | |
| 1 hour | |
| 5 hours | |
| 4 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{70mi}{70mph} \)
1 hour
| 0.8 | |
| 1.2 | |
| 1.4 | |
| 1 |
1
What is 6b2 + 6b2?
| 12b4 | |
| 12b-4 | |
| 2 | |
| 12b2 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
6b2 + 6b2
(6 + 6)b2
12b2
What is \( 9 \)\( \sqrt{32} \) + \( 9 \)\( \sqrt{2} \)
| 81\( \sqrt{2} \) | |
| 45\( \sqrt{2} \) | |
| 18\( \sqrt{64} \) | |
| 18\( \sqrt{2} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{32} \) + 9\( \sqrt{2} \)
9\( \sqrt{16 \times 2} \) + 9\( \sqrt{2} \)
9\( \sqrt{4^2 \times 2} \) + 9\( \sqrt{2} \)
(9)(4)\( \sqrt{2} \) + 9\( \sqrt{2} \)
36\( \sqrt{2} \) + 9\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
36\( \sqrt{2} \) + 9\( \sqrt{2} \)Betty scored 90% on her final exam. If each question was worth 2 points and there were 60 possible points on the exam, how many questions did Betty answer correctly?
| 12 | |
| 22 | |
| 27 | |
| 16 |
Betty scored 90% on the test meaning she earned 90% of the possible points on the test. There were 60 possible points on the test so she earned 60 x 0.9 = 54 points. Each question is worth 2 points so she got \( \frac{54}{2} \) = 27 questions right.