To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{9} \) x \( \frac{2}{8} \) = \( \frac{3 x 2}{9 x 8} \) = \( \frac{6}{72} \) = \(\frac{1}{12}\)

First, solve for \( \left|x + 3\right| \):

\( \left|x + 3\right| \) + 7 = 6
\( \left|x + 3\right| \) = 6 - 7
\( \left|x + 3\right| \) = -1

The value inside the absolute value brackets can be either positive or negative so (x + 3) must equal - 1 or --1 for \( \left|x + 3\right| \) to equal -1:

So, x = -2 or x = -4.

To simplify this fraction, first find the greatest common factor between them. The factors of 16 are [1, 2, 4, 8, 16] and the factors of 56 are [1, 2, 4, 7, 8, 14, 28, 56]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{16}{56} \) = \( \frac{\frac{16}{8}}{\frac{56}{8}} \) = \( \frac{2}{7} \)

To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 2 gallons so:

cans = \( \frac{4 \text{ gallons}}{2 \text{ gallons}} \) = 2

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

5z³ + 1z³
(5 + 1)z³
6z³