| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.44 |
| Score | 0% | 69% |
Frank loaned Christine $100 at an annual interest rate of 5%. If no payments are made, what is the total amount owed at the end of the first year?
| $108 | |
| $103 | |
| $105 | |
| $101 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $100
i = 0.05 x $100
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $100 + $5How many 6-passenger vans will it take to drive all 95 members of the football team to an away game?
| 7 vans | |
| 16 vans | |
| 2 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{95}{6} \) = 15\(\frac{5}{6}\)
So, it will take 15 full vans and one partially full van to transport the entire team making a total of 16 vans.
What is 5c2 x 8c6?
| 13c8 | |
| 13c12 | |
| 40c8 | |
| 40c6 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
5c2 x 8c6
(5 x 8)c(2 + 6)
40c8
Jennifer scored 94% on her final exam. If each question was worth 3 points and there were 300 possible points on the exam, how many questions did Jennifer answer correctly?
| 94 | |
| 98 | |
| 102 | |
| 96 |
Jennifer scored 94% on the test meaning she earned 94% of the possible points on the test. There were 300 possible points on the test so she earned 300 x 0.94 = 282 points. Each question is worth 3 points so she got \( \frac{282}{3} \) = 94 questions right.
What is \( \frac{4}{5} \) - \( \frac{8}{9} \)?
| 1 \( \frac{4}{45} \) | |
| -\(\frac{4}{45}\) | |
| 2 \( \frac{7}{45} \) | |
| \( \frac{3}{45} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 9}{5 x 9} \) - \( \frac{8 x 5}{9 x 5} \)
\( \frac{36}{45} \) - \( \frac{40}{45} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{36 - 40}{45} \) = \( \frac{-4}{45} \) = -\(\frac{4}{45}\)