ASVAB Arithmetic Reasoning Practice Test 793311 Results

Your Results Global Average
Questions 5 5
Correct 0 3.44
Score 0% 69%

Review

1

Frank loaned Christine $100 at an annual interest rate of 5%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$108
$103
$105
$101

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $100
i = 0.05 x $100

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $100 + $5
total = $105


2

How many 6-passenger vans will it take to drive all 95 members of the football team to an away game?

80% Answer Correctly
7 vans
16 vans
2 vans
9 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{95}{6} \) = 15\(\frac{5}{6}\)

So, it will take 15 full vans and one partially full van to transport the entire team making a total of 16 vans.


3

What is 5c2 x 8c6?

75% Answer Correctly
13c8
13c12
40c8
40c6

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

5c2 x 8c6
(5 x 8)c(2 + 6)
40c8


4

Jennifer scored 94% on her final exam. If each question was worth 3 points and there were 300 possible points on the exam, how many questions did Jennifer answer correctly?

57% Answer Correctly
94
98
102
96

Solution

Jennifer scored 94% on the test meaning she earned 94% of the possible points on the test. There were 300 possible points on the test so she earned 300 x 0.94 = 282 points. Each question is worth 3 points so she got \( \frac{282}{3} \) = 94 questions right.


5

What is \( \frac{4}{5} \) - \( \frac{8}{9} \)?

61% Answer Correctly
1 \( \frac{4}{45} \)
-\(\frac{4}{45}\)
2 \( \frac{7}{45} \)
\( \frac{3}{45} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 9}{5 x 9} \) - \( \frac{8 x 5}{9 x 5} \)

\( \frac{36}{45} \) - \( \frac{40}{45} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{36 - 40}{45} \) = \( \frac{-4}{45} \) = -\(\frac{4}{45}\)