| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.64 |
| Score | 0% | 73% |
4! = ?
4 x 3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
|
3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
How many 12-passenger vans will it take to drive all 52 members of the football team to an away game?
| 5 vans | |
| 9 vans | |
| 6 vans | |
| 10 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{52}{12} \) = 4\(\frac{1}{3}\)
So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.
What is 3a3 - 5a3?
| 8a6 | |
| -2a-3 | |
| -2a3 | |
| 8a-6 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
3a3 - 5a3
(3 - 5)a3
-2a3
If \( \left|z - 4\right| \) + 5 = 7, which of these is a possible value for z?
| -6 | |
| 21 | |
| 3 | |
| 2 |
First, solve for \( \left|z - 4\right| \):
\( \left|z - 4\right| \) + 5 = 7
\( \left|z - 4\right| \) = 7 - 5
\( \left|z - 4\right| \) = 2
The value inside the absolute value brackets can be either positive or negative so (z - 4) must equal + 2 or -2 for \( \left|z - 4\right| \) to equal 2:
| z - 4 = 2 z = 2 + 4 z = 6 | z - 4 = -2 z = -2 + 4 z = 2 |
So, z = 2 or z = 6.
What is -5a6 + 7a6?
| 12a6 | |
| 2a-12 | |
| 2a6 | |
| 12a-6 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-5a6 + 7a6
(-5 + 7)a6
2a6