ASVAB Arithmetic Reasoning Practice Test 795399 Results

Your Results Global Average
Questions 5 5
Correct 0 3.47
Score 0% 69%

Review

1

What is \( \frac{15\sqrt{21}}{3\sqrt{3}} \)?

71% Answer Correctly
5 \( \sqrt{\frac{1}{7}} \)
\(\frac{1}{5}\) \( \sqrt{\frac{1}{7}} \)
\(\frac{1}{5}\) \( \sqrt{7} \)
5 \( \sqrt{7} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{15\sqrt{21}}{3\sqrt{3}} \)
\( \frac{15}{3} \) \( \sqrt{\frac{21}{3}} \)
5 \( \sqrt{7} \)


2

Which of the following is a mixed number?

83% Answer Correctly

\({5 \over 7} \)

\({a \over 5} \)

\(1 {2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


3

What is \( \sqrt{\frac{25}{81}} \)?

70% Answer Correctly
\(\frac{1}{2}\)
\(\frac{3}{4}\)
1\(\frac{3}{4}\)
\(\frac{5}{9}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{25}{81}} \)
\( \frac{\sqrt{25}}{\sqrt{81}} \)
\( \frac{\sqrt{5^2}}{\sqrt{9^2}} \)
\(\frac{5}{9}\)


4

Bob loaned Jennifer $100 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$103
$105
$108
$104

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $100
i = 0.03 x $100

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $100 + $3
total = $103


5

A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 7 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.

How many error-free parts did the machine produce yesterday?

48% Answer Correctly
213.4
149.4
124.1
69

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{3}{100} \) x 7 = \( \frac{3 \times 7}{100} \) = \( \frac{21}{100} \) = 0.21 errors per hour

So, in an average hour, the machine will produce 7 - 0.21 = 6.79 error free parts.

The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 6.79 = 149.4 error free parts were produced yesterday.