| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
What is \( \frac{5}{5} \) - \( \frac{6}{7} \)?
| \( \frac{7}{13} \) | |
| \(\frac{1}{7}\) | |
| 2 \( \frac{1}{10} \) | |
| \( \frac{9}{16} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{5 x 7}{5 x 7} \) - \( \frac{6 x 5}{7 x 5} \)
\( \frac{35}{35} \) - \( \frac{30}{35} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{35 - 30}{35} \) = \( \frac{5}{35} \) = \(\frac{1}{7}\)
What is (b4)2?
| b2 | |
| 4b2 | |
| b8 | |
| b6 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b4)2\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
|
commutative property for division |
|
commutative property for multiplication |
|
distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
Latoya scored 78% on her final exam. If each question was worth 2 points and there were 120 possible points on the exam, how many questions did Latoya answer correctly?
| 48 | |
| 47 | |
| 62 | |
| 36 |
Latoya scored 78% on the test meaning she earned 78% of the possible points on the test. There were 120 possible points on the test so she earned 120 x 0.78 = 94 points. Each question is worth 2 points so she got \( \frac{94}{2} \) = 47 questions right.
If the ratio of home fans to visiting fans in a crowd is 3:1 and all 40,000 seats in a stadium are filled, how many home fans are in attendance?
| 24,667 | |
| 30,000 | |
| 24,000 | |
| 28,667 |
A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:
40,000 fans x \( \frac{3}{4} \) = \( \frac{120000}{4} \) = 30,000 fans.