| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.45 |
| Score | 0% | 69% |
What is (x5)5?
| x25 | |
| x10 | |
| 5x5 | |
| x0 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x5)5How many 6-passenger vans will it take to drive all 62 members of the football team to an away game?
| 10 vans | |
| 11 vans | |
| 6 vans | |
| 5 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{62}{6} \) = 10\(\frac{1}{3}\)
So, it will take 10 full vans and one partially full van to transport the entire team making a total of 11 vans.
What is \( \frac{10\sqrt{4}}{5\sqrt{2}} \)?
| 2 \( \sqrt{2} \) | |
| \(\frac{1}{2}\) \( \sqrt{\frac{1}{2}} \) | |
| \(\frac{1}{2}\) \( \sqrt{2} \) | |
| 2 \( \sqrt{\frac{1}{2}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{10\sqrt{4}}{5\sqrt{2}} \)
\( \frac{10}{5} \) \( \sqrt{\frac{4}{2}} \)
2 \( \sqrt{2} \)
11 members of a bridal party need transported to a wedding reception but there are only 2 4-passenger taxis available to take them. How many will need to find other transportation?
| 4 | |
| 2 | |
| 9 | |
| 3 |
There are 2 4-passenger taxis available so that's 2 x 4 = 8 total seats. There are 11 people needing transportation leaving 11 - 8 = 3 who will have to find other transportation.
What is \( 2 \)\( \sqrt{112} \) - \( 2 \)\( \sqrt{7} \)
| 4\( \sqrt{7} \) | |
| 0\( \sqrt{33} \) | |
| 0\( \sqrt{16} \) | |
| 6\( \sqrt{7} \) |
To subtract these radicals together their radicands must be the same:
2\( \sqrt{112} \) - 2\( \sqrt{7} \)
2\( \sqrt{16 \times 7} \) - 2\( \sqrt{7} \)
2\( \sqrt{4^2 \times 7} \) - 2\( \sqrt{7} \)
(2)(4)\( \sqrt{7} \) - 2\( \sqrt{7} \)
8\( \sqrt{7} \) - 2\( \sqrt{7} \)
Now that the radicands are identical, you can subtract them:
8\( \sqrt{7} \) - 2\( \sqrt{7} \)