| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
Simplify \( \frac{16}{64} \).
| \( \frac{8}{19} \) | |
| \( \frac{6}{19} \) | |
| \( \frac{1}{4} \) | |
| \( \frac{8}{15} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 16 are [1, 2, 4, 8, 16] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 5 factors [1, 2, 4, 8, 16] making 16 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{16}{64} \) = \( \frac{\frac{16}{16}}{\frac{64}{16}} \) = \( \frac{1}{4} \)
What is (b4)5?
| b20 | |
| 4b5 | |
| b9 | |
| 5b4 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b4)5What is \( 8 \)\( \sqrt{32} \) + \( 6 \)\( \sqrt{2} \)
| 48\( \sqrt{16} \) | |
| 48\( \sqrt{2} \) | |
| 38\( \sqrt{2} \) | |
| 48\( \sqrt{64} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{32} \) + 6\( \sqrt{2} \)
8\( \sqrt{16 \times 2} \) + 6\( \sqrt{2} \)
8\( \sqrt{4^2 \times 2} \) + 6\( \sqrt{2} \)
(8)(4)\( \sqrt{2} \) + 6\( \sqrt{2} \)
32\( \sqrt{2} \) + 6\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
32\( \sqrt{2} \) + 6\( \sqrt{2} \)11 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?
| 2 | |
| 9 | |
| 5 | |
| 4 |
There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 11 people needing transportation leaving 11 - 9 = 2 who will have to find other transportation.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 65% larger than the original. By what percentage has the area of the logo increased?
| 15% | |
| 17\(\frac{1}{2}\)% | |
| 25% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 65% the radius (and, consequently, the total area) increases by \( \frac{65\text{%}}{2} \) = 32\(\frac{1}{2}\)%