To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{9} \) x \( \frac{1}{8} \) = \( \frac{1 x 1}{9 x 8} \) = \( \frac{1}{72} \) = \(\frac{1}{72}\)

There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 17 people needing transportation leaving 17 - 16 = 1 who will have to find other transportation.

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).

First, solve for \( \left|z + 2\right| \):

\( \left|z + 2\right| \) + 1 = -6
\( \left|z + 2\right| \) = -6 - 1
\( \left|z + 2\right| \) = -7

The value inside the absolute value brackets can be either positive or negative so (z + 2) must equal - 7 or --7 for \( \left|z + 2\right| \) to equal -7:

So, z = 5 or z = -9.

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-x^5}{6x^3} \)
\( \frac{-1}{6} \) x^{(5 - 3)}
-\(\frac{1}{6}\)x²