There are 4 5-passenger taxis available so that's 4 x 5 = 20 total seats. There are 22 people needing transportation leaving 22 - 20 = 2 who will have to find other transportation.

First, solve for \( \left|c - 6\right| \):

\( \left|c - 6\right| \) + 9 = -1
\( \left|c - 6\right| \) = -1 - 9
\( \left|c - 6\right| \) = -10

The value inside the absolute value brackets can be either positive or negative so (c - 6) must equal - 10 or --10 for \( \left|c - 6\right| \) to equal -10:

So, c = 16 or c = -4.

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-2c^7}{7c^3} \)
\( \frac{-2}{7} \) c^{(7 - 3)}
-\(\frac{2}{7}\)c⁴

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 3}{2 x 3} \) + \( \frac{5 x 1}{6 x 1} \)

\( \frac{24}{6} \) + \( \frac{5}{6} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{24 + 5}{6} \) = \( \frac{29}{6} \) = 4\(\frac{5}{6}\)