| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
Which of the following is not an integer?
\({1 \over 2}\) |
|
1 |
|
-1 |
|
0 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
Damon loaned Monica $1,200 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,272 | |
| $1,212 | |
| $1,236 | |
| $1,284 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,200
i = 0.06 x $1,200
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,200 + $72Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 17 small cakes per hour. The kitchen is available for 3 hours and 35 large cakes and 330 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 10 | |
| 5 | |
| 6 | |
| 9 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 4 x 3 = 12 large cakes during that time. 35 large cakes are needed for the party so \( \frac{35}{12} \) = 2\(\frac{11}{12}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 17 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 17 x 3 = 51 small cakes during that time. 330 small cakes are needed for the party so \( \frac{330}{51} \) = 6\(\frac{8}{17}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 7 = 10 cooks.
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?
| 5 | |
| 8 | |
| 4 | |
| 2 |
To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2
4! = ?
4 x 3 |
|
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.