The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{9}{100} \) x 6 = \( \frac{9 \times 6}{100} \) = \( \frac{54}{100} \) = 0.54 errors per hour

So, in an average hour, the machine will produce 6 - 0.54 = 5.46 error free parts.

The machine ran for 24 - 5 = 19 hours yesterday so you would expect that 19 x 5.46 = 103.7 error free parts were produced yesterday.

If a single cook can bake 4 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 4 x 3 = 12 large cakes during that time. 34 large cakes are needed for the party so \( \frac{34}{12} \) = 2\(\frac{5}{6}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 12 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 12 x 3 = 36 small cakes during that time. 460 small cakes are needed for the party so \( \frac{460}{36} \) = 12\(\frac{7}{9}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 13 = 16 cooks.

If 49% of the town's 43,000 voters cast ballots the number of votes cast is:

(\( \frac{49}{100} \)) x 43,000 = \( \frac{2,107,000}{100} \) = 21,070

The mayor got 87% of the votes cast which is:

(\( \frac{87}{100} \)) x 21,070 = \( \frac{1,833,090}{100} \) = 18,331 votes.

There are 2 4-passenger taxis available so that's 2 x 4 = 8 total seats. There are 11 people needing transportation leaving 11 - 8 = 3 who will have to find other transportation.

The amount of flour you need is (1\(\frac{7}{8}\) - 1\(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{15}{8} \) - \( \frac{13}{8} \)) cups
\( \frac{2}{8} \) cups
\(\frac{1}{4}\) cups