ASVAB Arithmetic Reasoning Practice Test 807845 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

Frank loaned Betty $1,200 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$1,236
$1,284
$1,296
$1,248

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,200
i = 0.08 x $1,200

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,200 + $96
total = $1,296


2

Solve 2 + (5 + 5) ÷ 2 x 2 - 52

53% Answer Correctly
1\(\frac{1}{4}\)
2\(\frac{1}{4}\)
1\(\frac{2}{7}\)
-13

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (5 + 5) ÷ 2 x 2 - 52
P: 2 + (10) ÷ 2 x 2 - 52
E: 2 + 10 ÷ 2 x 2 - 25
MD: 2 + \( \frac{10}{2} \) x 2 - 25
MD: 2 + \( \frac{20}{2} \) - 25
AS: \( \frac{4}{2} \) + \( \frac{20}{2} \) - 25
AS: \( \frac{24}{2} \) - 25
AS: \( \frac{24 - 50}{2} \)
\( \frac{-26}{2} \)
-13


3

What is the least common multiple of 8 and 12?

72% Answer Correctly
93
24
16
92

Solution

The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 have in common.


4

A bread recipe calls for 2\(\frac{3}{4}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?

62% Answer Correctly
2\(\frac{1}{4}\) cups
1\(\frac{3}{4}\) cups
2\(\frac{1}{8}\) cups
1\(\frac{5}{8}\) cups

Solution

The amount of flour you need is (2\(\frac{3}{4}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{22}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{13}{8} \) cups
1\(\frac{5}{8}\) cups


5

13 members of a bridal party need transported to a wedding reception but there are only 4 3-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
2
6
1
9

Solution

There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 13 people needing transportation leaving 13 - 12 = 1 who will have to find other transportation.