ASVAB Arithmetic Reasoning Practice Test 808199 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

If a mayor is elected with 90% of the votes cast and 72% of a town's 37,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
14,386
21,578
18,914
23,976

Solution

If 72% of the town's 37,000 voters cast ballots the number of votes cast is:

(\( \frac{72}{100} \)) x 37,000 = \( \frac{2,664,000}{100} \) = 26,640

The mayor got 90% of the votes cast which is:

(\( \frac{90}{100} \)) x 26,640 = \( \frac{2,397,600}{100} \) = 23,976 votes.


2

What is \( \sqrt{\frac{9}{25}} \)?

70% Answer Correctly
4
\(\frac{1}{3}\)
1
\(\frac{3}{5}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{9}{25}} \)
\( \frac{\sqrt{9}}{\sqrt{25}} \)
\( \frac{\sqrt{3^2}}{\sqrt{5^2}} \)
\(\frac{3}{5}\)


3

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for multiplication

commutative property for multiplication

distributive property for division

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


4

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

integer

fraction

improper fraction

mixed number


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


5

What is \( 3 \)\( \sqrt{80} \) - \( 9 \)\( \sqrt{5} \)

38% Answer Correctly
-6\( \sqrt{9} \)
3\( \sqrt{5} \)
27\( \sqrt{16} \)
27\( \sqrt{80} \)

Solution

To subtract these radicals together their radicands must be the same:

3\( \sqrt{80} \) - 9\( \sqrt{5} \)
3\( \sqrt{16 \times 5} \) - 9\( \sqrt{5} \)
3\( \sqrt{4^2 \times 5} \) - 9\( \sqrt{5} \)
(3)(4)\( \sqrt{5} \) - 9\( \sqrt{5} \)
12\( \sqrt{5} \) - 9\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

12\( \sqrt{5} \) - 9\( \sqrt{5} \)
(12 - 9)\( \sqrt{5} \)
3\( \sqrt{5} \)