| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
If a mayor is elected with 90% of the votes cast and 72% of a town's 37,000 voters cast a vote, how many votes did the mayor receive?
| 14,386 | |
| 21,578 | |
| 18,914 | |
| 23,976 |
If 72% of the town's 37,000 voters cast ballots the number of votes cast is:
(\( \frac{72}{100} \)) x 37,000 = \( \frac{2,664,000}{100} \) = 26,640
The mayor got 90% of the votes cast which is:
(\( \frac{90}{100} \)) x 26,640 = \( \frac{2,397,600}{100} \) = 23,976 votes.
What is \( \sqrt{\frac{9}{25}} \)?
| 4 | |
| \(\frac{1}{3}\) | |
| 1 | |
| \(\frac{3}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{25}} \)
\( \frac{\sqrt{9}}{\sqrt{25}} \)
\( \frac{\sqrt{3^2}}{\sqrt{5^2}} \)
\(\frac{3}{5}\)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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commutative property for multiplication |
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distributive property for division |
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commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
A factor is a positive __________ that divides evenly into a given number.
integer |
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fraction |
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improper fraction |
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mixed number |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
What is \( 3 \)\( \sqrt{80} \) - \( 9 \)\( \sqrt{5} \)
| -6\( \sqrt{9} \) | |
| 3\( \sqrt{5} \) | |
| 27\( \sqrt{16} \) | |
| 27\( \sqrt{80} \) |
To subtract these radicals together their radicands must be the same:
3\( \sqrt{80} \) - 9\( \sqrt{5} \)
3\( \sqrt{16 \times 5} \) - 9\( \sqrt{5} \)
3\( \sqrt{4^2 \times 5} \) - 9\( \sqrt{5} \)
(3)(4)\( \sqrt{5} \) - 9\( \sqrt{5} \)
12\( \sqrt{5} \) - 9\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
12\( \sqrt{5} \) - 9\( \sqrt{5} \)