| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
On average, the center for a basketball team hits 45% of his shots while a guard on the same team hits 65% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 39 | |
| 20 | |
| 43 | |
| 17 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{65}{100} \) = \( \frac{65 x 15}{100} \) = \( \frac{975}{100} \) = 9 shots
The center makes 45% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{9}{\frac{45}{100}} \) = 9 x \( \frac{100}{45} \) = \( \frac{9 x 100}{45} \) = \( \frac{900}{45} \) = 20 shots
to make the same number of shots as the guard and thus score the same number of points.
What is -8c4 x 5c4?
| -40c16 | |
| -40c4 | |
| -40c0 | |
| -40c8 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-8c4 x 5c4
(-8 x 5)c(4 + 4)
-40c8
What is \( \frac{2}{6} \) + \( \frac{3}{10} \)?
| 2 \( \frac{7}{15} \) | |
| \(\frac{19}{30}\) | |
| \( \frac{7}{10} \) | |
| \( \frac{1}{6} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 5}{6 x 5} \) + \( \frac{3 x 3}{10 x 3} \)
\( \frac{10}{30} \) + \( \frac{9}{30} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{10 + 9}{30} \) = \( \frac{19}{30} \) = \(\frac{19}{30}\)
15 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 5 | |
| 8 | |
| 3 | |
| 9 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 15 people needing transportation leaving 15 - 12 = 3 who will have to find other transportation.
Find the average of the following numbers: 19, 11, 18, 12.
| 17 | |
| 20 | |
| 15 | |
| 13 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{19 + 11 + 18 + 12}{4} \) = \( \frac{60}{4} \) = 15