| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
Damon loaned Christine $600 at an annual interest rate of 5%. If no payments are made, what is the total amount owed at the end of the first year?
| $612 | |
| $630 | |
| $654 | |
| $624 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $600
i = 0.05 x $600
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $600 + $30If there were a total of 350 raffle tickets sold and you bought 31 tickets, what's the probability that you'll win the raffle?
| 13% | |
| 6% | |
| 15% | |
| 9% |
You have 31 out of the total of 350 raffle tickets sold so you have a (\( \frac{31}{350} \)) x 100 = \( \frac{31 \times 100}{350} \) = \( \frac{3100}{350} \) = 9% chance to win the raffle.
Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 17 small cakes per hour. The kitchen is available for 3 hours and 40 large cakes and 280 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 5 | |
| 12 | |
| 10 | |
| 80 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 4 x 3 = 12 large cakes during that time. 40 large cakes are needed for the party so \( \frac{40}{12} \) = 3\(\frac{1}{3}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 17 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 17 x 3 = 51 small cakes during that time. 280 small cakes are needed for the party so \( \frac{280}{51} \) = 5\(\frac{25}{51}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 4 + 6 = 10 cooks.
What is the greatest common factor of 40 and 20?
| 20 | |
| 2 | |
| 4 | |
| 6 |
The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 20 are [1, 2, 4, 5, 10, 20]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 the greatest factor 40 and 20 have in common.
Diane scored 94% on her final exam. If each question was worth 4 points and there were 360 possible points on the exam, how many questions did Diane answer correctly?
| 89 | |
| 71 | |
| 99 | |
| 85 |
Diane scored 94% on the test meaning she earned 94% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.94 = 340 points. Each question is worth 4 points so she got \( \frac{340}{4} \) = 85 questions right.