To subtract these radicals together their radicands must be the same:

8\( \sqrt{125} \) - 4\( \sqrt{5} \)
8\( \sqrt{25 \times 5} \) - 4\( \sqrt{5} \)
8\( \sqrt{5^2 \times 5} \) - 4\( \sqrt{5} \)
(8)(5)\( \sqrt{5} \) - 4\( \sqrt{5} \)
40\( \sqrt{5} \) - 4\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

40\( \sqrt{5} \) - 4\( \sqrt{5} \)
(40 - 4)\( \sqrt{5} \)
36\( \sqrt{5} \)

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(x²)⁵
x^{(2 * 5)}
x¹⁰

By buying two shirts, Monty will save $24 x \( \frac{10}{100} \) = \( \frac{$24 x 10}{100} \) = \( \frac{$240}{100} \) = $2.40 on the second shirt.

So, his total cost will be
$24.00 + ($24.00 - $2.40)
$24.00 + $21.60
$45.60

First, solve for \( \left|b - 6\right| \):

\( \left|b - 6\right| \) + 7 = 2
\( \left|b - 6\right| \) = 2 - 7
\( \left|b - 6\right| \) = -5

The value inside the absolute value brackets can be either positive or negative so (b - 6) must equal - 5 or --5 for \( \left|b - 6\right| \) to equal -5:

b - 6 = -5 b = -5 + 6 b = 1

b - 6 = 5 b = 5 + 6 b = 11

So, b = 11 or b = 1.

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 9h \)
360 miles