| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
| Score | 0% | 55% |
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{9} \) | |
| \( \frac{1}{840} \) | |
| \( \frac{1}{120} \) | |
| \( \frac{1}{360} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)
How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?
| 3 | |
| 8 | |
| 4 | |
| 4 |
To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4
A bread recipe calls for 2\(\frac{5}{8}\) cups of flour. If you only have \(\frac{1}{4}\) cup, how much more flour is needed?
| 1\(\frac{1}{2}\) cups | |
| 2\(\frac{3}{8}\) cups | |
| 2\(\frac{7}{8}\) cups | |
| 2\(\frac{1}{2}\) cups |
The amount of flour you need is (2\(\frac{5}{8}\) - \(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{21}{8} \) - \( \frac{2}{8} \)) cups
\( \frac{19}{8} \) cups
2\(\frac{3}{8}\) cups
Solve 3 + (4 + 4) ÷ 2 x 2 - 32
| \(\frac{4}{7}\) | |
| \(\frac{7}{8}\) | |
| \(\frac{1}{3}\) | |
| 2 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (4 + 4) ÷ 2 x 2 - 32
P: 3 + (8) ÷ 2 x 2 - 32
E: 3 + 8 ÷ 2 x 2 - 9
MD: 3 + \( \frac{8}{2} \) x 2 - 9
MD: 3 + \( \frac{16}{2} \) - 9
AS: \( \frac{6}{2} \) + \( \frac{16}{2} \) - 9
AS: \( \frac{22}{2} \) - 9
AS: \( \frac{22 - 18}{2} \)
\( \frac{4}{2} \)
2
Which of the following statements about exponents is false?
b1 = b |
|
b1 = 1 |
|
b0 = 1 |
|
all of these are false |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).