ASVAB Arithmetic Reasoning Practice Test 810317 Results

Your Results Global Average
Questions 5 5
Correct 0 2.77
Score 0% 55%

Review

1

Solve for \( \frac{2!}{6!} \)

66% Answer Correctly
\( \frac{1}{9} \)
\( \frac{1}{840} \)
\( \frac{1}{120} \)
\( \frac{1}{360} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)


2

How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?

52% Answer Correctly
3
8
4
4

Solution

To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:

cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4


3

A bread recipe calls for 2\(\frac{5}{8}\) cups of flour. If you only have \(\frac{1}{4}\) cup, how much more flour is needed?

62% Answer Correctly
1\(\frac{1}{2}\) cups
2\(\frac{3}{8}\) cups
2\(\frac{7}{8}\) cups
2\(\frac{1}{2}\) cups

Solution

The amount of flour you need is (2\(\frac{5}{8}\) - \(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{21}{8} \) - \( \frac{2}{8} \)) cups
\( \frac{19}{8} \) cups
2\(\frac{3}{8}\) cups


4

Solve 3 + (4 + 4) ÷ 2 x 2 - 32

52% Answer Correctly
\(\frac{4}{7}\)
\(\frac{7}{8}\)
\(\frac{1}{3}\)
2

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (4 + 4) ÷ 2 x 2 - 32
P: 3 + (8) ÷ 2 x 2 - 32
E: 3 + 8 ÷ 2 x 2 - 9
MD: 3 + \( \frac{8}{2} \) x 2 - 9
MD: 3 + \( \frac{16}{2} \) - 9
AS: \( \frac{6}{2} \) + \( \frac{16}{2} \) - 9
AS: \( \frac{22}{2} \) - 9
AS: \( \frac{22 - 18}{2} \)
\( \frac{4}{2} \)
2


5

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = b

b1 = 1

b0 = 1

all of these are false


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).