| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 61 | |
| 62 | |
| 66 | |
| 60 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61
What is the least common multiple of 5 and 9?
| 35 | |
| 45 | |
| 4 | |
| 42 |
The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 have in common.
Solve for \( \frac{6!}{4!} \)
| \( \frac{1}{840} \) | |
| 6 | |
| \( \frac{1}{4} \) | |
| 30 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{6!}{4!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{6 \times 5}{1} \)
\( 6 \times 5 \)
30
Jennifer scored 96% on her final exam. If each question was worth 3 points and there were 240 possible points on the exam, how many questions did Jennifer answer correctly?
| 79 | |
| 64 | |
| 75 | |
| 77 |
Jennifer scored 96% on the test meaning she earned 96% of the possible points on the test. There were 240 possible points on the test so she earned 240 x 0.96 = 231 points. Each question is worth 3 points so she got \( \frac{231}{3} \) = 77 questions right.
If \(\left|a\right| = 7\), which of the following best describes a?
a = 7 |
|
a = -7 |
|
a = 7 or a = -7 |
|
none of these is correct |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).