| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
Which of the following is a mixed number?
\({5 \over 7} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
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\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Simplify \( \frac{20}{76} \).
| \( \frac{7}{11} \) | |
| \( \frac{9}{17} \) | |
| \( \frac{5}{19} \) | |
| \( \frac{6}{19} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{20}{76} \) = \( \frac{\frac{20}{4}}{\frac{76}{4}} \) = \( \frac{5}{19} \)
What is 7\( \sqrt{6} \) x 4\( \sqrt{8} \)?
| 112\( \sqrt{3} \) | |
| 11\( \sqrt{8} \) | |
| 11\( \sqrt{48} \) | |
| 28\( \sqrt{8} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
7\( \sqrt{6} \) x 4\( \sqrt{8} \)
(7 x 4)\( \sqrt{6 \times 8} \)
28\( \sqrt{48} \)
Now we need to simplify the radical:
28\( \sqrt{48} \)
28\( \sqrt{3 \times 16} \)
28\( \sqrt{3 \times 4^2} \)
(28)(4)\( \sqrt{3} \)
112\( \sqrt{3} \)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 10% off." If Charlie buys two shirts, each with a regular price of $28, how much will he pay for both shirts?
| $36.40 | |
| $35.00 | |
| $53.20 | |
| $2.80 |
By buying two shirts, Charlie will save $28 x \( \frac{10}{100} \) = \( \frac{$28 x 10}{100} \) = \( \frac{$280}{100} \) = $2.80 on the second shirt.
So, his total cost will be
$28.00 + ($28.00 - $2.80)
$28.00 + $25.20
$53.20
If all of a roofing company's 16 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 2 | |
| 18 | |
| 12 | |
| 16 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 7 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 7 x 4 = 28 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 28 - 16 = 12 new staff for the busy season.