ASVAB Arithmetic Reasoning Practice Test 817552 Results

Your Results Global Average
Questions 5 5
Correct 0 3.61
Score 0% 72%

Review

1

Which of the following is a mixed number?

82% Answer Correctly

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({5 \over 7} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

mixed number

integer

fraction

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


3

Solve for \( \frac{3!}{5!} \)

67% Answer Correctly
\( \frac{1}{6} \)
72
\( \frac{1}{20} \)
\( \frac{1}{9} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)


4

What is 2\( \sqrt{7} \) x 7\( \sqrt{7} \)?

41% Answer Correctly
98
14\( \sqrt{7} \)
14\( \sqrt{14} \)
9\( \sqrt{7} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

2\( \sqrt{7} \) x 7\( \sqrt{7} \)
(2 x 7)\( \sqrt{7 \times 7} \)
14\( \sqrt{49} \)

Now we need to simplify the radical:

14\( \sqrt{49} \)
14\( \sqrt{7^2} \)
(14)(7)
98


5

What is the next number in this sequence: 1, 2, 3, 4, 5, __________ ?

92% Answer Correctly
9
12
4
6

Solution

The equation for this sequence is:

an = an-1 + 1

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 1
a6 = 5 + 1
a6 = 6