ASVAB Arithmetic Reasoning Practice Test 817610 Results

Your Results Global Average
Questions 5 5
Correct 0 3.25
Score 0% 65%

Review

1

What is 8a7 - 5a7?

71% Answer Correctly
-3a7
13a49
3a7
-3a-7

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

8a7 - 5a7
(8 - 5)a7
3a7


2

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

associative

distributive

commutative

PEDMAS


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


3

4! = ?

84% Answer Correctly

4 x 3 x 2 x 1

4 x 3

5 x 4 x 3 x 2 x 1

3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


4

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

commutative property for multiplication

distributive property for division

distributive property for multiplication

commutative property for division


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


5

What is \( 5 \)\( \sqrt{48} \) + \( 7 \)\( \sqrt{3} \)

35% Answer Correctly
12\( \sqrt{48} \)
12\( \sqrt{3} \)
27\( \sqrt{3} \)
12\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

5\( \sqrt{48} \) + 7\( \sqrt{3} \)
5\( \sqrt{16 \times 3} \) + 7\( \sqrt{3} \)
5\( \sqrt{4^2 \times 3} \) + 7\( \sqrt{3} \)
(5)(4)\( \sqrt{3} \) + 7\( \sqrt{3} \)
20\( \sqrt{3} \) + 7\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

20\( \sqrt{3} \) + 7\( \sqrt{3} \)
(20 + 7)\( \sqrt{3} \)
27\( \sqrt{3} \)