ASVAB Arithmetic Reasoning Practice Test 820757 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

Solve 2 + (4 + 2) ÷ 2 x 4 - 32

52% Answer Correctly
5
3
1
\(\frac{3}{4}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (4 + 2) ÷ 2 x 4 - 32
P: 2 + (6) ÷ 2 x 4 - 32
E: 2 + 6 ÷ 2 x 4 - 9
MD: 2 + \( \frac{6}{2} \) x 4 - 9
MD: 2 + \( \frac{24}{2} \) - 9
AS: \( \frac{4}{2} \) + \( \frac{24}{2} \) - 9
AS: \( \frac{28}{2} \) - 9
AS: \( \frac{28 - 18}{2} \)
\( \frac{10}{2} \)
5


2

What is \( 4 \)\( \sqrt{45} \) + \( 9 \)\( \sqrt{5} \)

35% Answer Correctly
13\( \sqrt{45} \)
21\( \sqrt{5} \)
13\( \sqrt{9} \)
36\( \sqrt{9} \)

Solution

To add these radicals together their radicands must be the same:

4\( \sqrt{45} \) + 9\( \sqrt{5} \)
4\( \sqrt{9 \times 5} \) + 9\( \sqrt{5} \)
4\( \sqrt{3^2 \times 5} \) + 9\( \sqrt{5} \)
(4)(3)\( \sqrt{5} \) + 9\( \sqrt{5} \)
12\( \sqrt{5} \) + 9\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{5} \) + 9\( \sqrt{5} \)
(12 + 9)\( \sqrt{5} \)
21\( \sqrt{5} \)


3

If a mayor is elected with 51% of the votes cast and 83% of a town's 32,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
13,546
18,326
23,904
22,576

Solution

If 83% of the town's 32,000 voters cast ballots the number of votes cast is:

(\( \frac{83}{100} \)) x 32,000 = \( \frac{2,656,000}{100} \) = 26,560

The mayor got 51% of the votes cast which is:

(\( \frac{51}{100} \)) x 26,560 = \( \frac{1,354,560}{100} \) = 13,546 votes.


4

4! = ?

84% Answer Correctly

4 x 3 x 2 x 1

5 x 4 x 3 x 2 x 1

4 x 3

3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


5

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

68% Answer Correctly
36
38
31
25

Solution

The equation for this sequence is:

an = an-1 + 2(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31