| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
distributive |
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associative |
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PEDMAS |
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commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
On average, the center for a basketball team hits 45% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 23 | |
| 14 | |
| 18 | |
| 15 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{55}{100} \) = \( \frac{55 x 15}{100} \) = \( \frac{825}{100} \) = 8 shots
The center makes 45% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{8}{\frac{45}{100}} \) = 8 x \( \frac{100}{45} \) = \( \frac{8 x 100}{45} \) = \( \frac{800}{45} \) = 18 shots
to make the same number of shots as the guard and thus score the same number of points.
Find the average of the following numbers: 12, 6, 13, 5.
| 9 | |
| 12 | |
| 4 | |
| 6 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{12 + 6 + 13 + 5}{4} \) = \( \frac{36}{4} \) = 9
What is \( \frac{7}{5} \) - \( \frac{8}{7} \)?
| \(\frac{9}{35}\) | |
| 2 \( \frac{7}{14} \) | |
| 2 \( \frac{2}{10} \) | |
| 1 \( \frac{5}{35} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 7}{5 x 7} \) - \( \frac{8 x 5}{7 x 5} \)
\( \frac{49}{35} \) - \( \frac{40}{35} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{49 - 40}{35} \) = \( \frac{9}{35} \) = \(\frac{9}{35}\)
4! = ?
4 x 3 |
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4 x 3 x 2 x 1 |
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5 x 4 x 3 x 2 x 1 |
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3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.