There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 17 people needing transportation leaving 17 - 15 = 2 who will have to find other transportation.

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 36 meters so the equation becomes: 2w + 2h = 36.

Putting these two equations together and solving for width (w):

2w + 2h = 36
w + h = \( \frac{36}{2} \)
w + h = 18
w = 18 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 18 - 2w
3w = 18
w = \( \frac{18}{3} \)
w = 6

Since h = 2w that makes h = (2 x 6) = 12 and the area = h x w = 6 x 12 = 72 m²

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{6 x 7}{3 x 7} \) - \( \frac{6 x 3}{7 x 3} \)

\( \frac{42}{21} \) - \( \frac{18}{21} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{42 - 18}{21} \) = \( \frac{24}{21} \) = 1\(\frac{1}{7}\)

40% of the water consumption is industrial use and 23% is personal use so (40% - 23%) = 17% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{17}{100} \) x 20,000 gallons = 3,400 gallons.

The greatest common factor (GCF) is the greatest factor that divides two integers.