ASVAB Arithmetic Reasoning Practice Test 824418 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

4! = ?

84% Answer Correctly

4 x 3 x 2 x 1

3 x 2 x 1

4 x 3

5 x 4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 40% off." If Charlie buys two shirts, each with a regular price of $44, how much will he pay for both shirts?

56% Answer Correctly
$55.00
$26.40
$70.40
$50.60

Solution

By buying two shirts, Charlie will save $44 x \( \frac{40}{100} \) = \( \frac{$44 x 40}{100} \) = \( \frac{$1760}{100} \) = $17.60 on the second shirt.

So, his total cost will be
$44.00 + ($44.00 - $17.60)
$44.00 + $26.40
$70.40


3

If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 9 complete crews out on jobs?

55% Answer Correctly
13
12
4
2

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 9 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 9 x 3 = 27 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 27 - 15 = 12 new staff for the busy season.


4

Which of the following is not a prime number?

64% Answer Correctly

2

7

5

9


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


5

Solve for \( \frac{6!}{2!} \)

66% Answer Correctly
\( \frac{1}{56} \)
\( \frac{1}{9} \)
120
360

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{6!}{2!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{6 \times 5 \times 4 \times 3}{1} \)
\( 6 \times 5 \times 4 \times 3 \)
360