ASVAB Arithmetic Reasoning Practice Test 828892 Results

Your Results Global Average
Questions 5 5
Correct 0 2.65
Score 0% 53%

Review

1

What is \( 5 \)\( \sqrt{8} \) + \( 3 \)\( \sqrt{2} \)

35% Answer Correctly
15\( \sqrt{16} \)
15\( \sqrt{8} \)
15\( \sqrt{2} \)
13\( \sqrt{2} \)

Solution

To add these radicals together their radicands must be the same:

5\( \sqrt{8} \) + 3\( \sqrt{2} \)
5\( \sqrt{4 \times 2} \) + 3\( \sqrt{2} \)
5\( \sqrt{2^2 \times 2} \) + 3\( \sqrt{2} \)
(5)(2)\( \sqrt{2} \) + 3\( \sqrt{2} \)
10\( \sqrt{2} \) + 3\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

10\( \sqrt{2} \) + 3\( \sqrt{2} \)
(10 + 3)\( \sqrt{2} \)
13\( \sqrt{2} \)


2

A tiger in a zoo has consumed 70 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 140 pounds?

56% Answer Correctly
7
6
9
5

Solution

If the tiger has consumed 70 pounds of food in 5 days that's \( \frac{70}{5} \) = 14 pounds of food per day. The tiger needs to consume 140 - 70 = 70 more pounds of food to reach 140 pounds total. At 14 pounds of food per day that's \( \frac{70}{14} \) = 5 more days.


3

A circular logo is enlarged to fit the lid of a jar. The new diameter is 55% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
15%
22\(\frac{1}{2}\)%
17\(\frac{1}{2}\)%
27\(\frac{1}{2}\)%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 55% the radius (and, consequently, the total area) increases by \( \frac{55\text{%}}{2} \) = 27\(\frac{1}{2}\)%


4

A machine in a factory has an error rate of 5 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 6 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
86.4
172.9
85.5
97.9

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{5}{100} \) x 5 = \( \frac{5 \times 5}{100} \) = \( \frac{25}{100} \) = 0.25 errors per hour

So, in an average hour, the machine will produce 5 - 0.25 = 4.75 error free parts.

The machine ran for 24 - 6 = 18 hours yesterday so you would expect that 18 x 4.75 = 85.5 error free parts were produced yesterday.


5

Find the average of the following numbers: 7, 5, 8, 4.

74% Answer Correctly
5
2
9
6

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{7 + 5 + 8 + 4}{4} \) = \( \frac{24}{4} \) = 6