| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
What is \( 9 \)\( \sqrt{125} \) + \( 3 \)\( \sqrt{5} \)
| 27\( \sqrt{125} \) | |
| 48\( \sqrt{5} \) | |
| 12\( \sqrt{125} \) | |
| 27\( \sqrt{5} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{125} \) + 3\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) + 3\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) + 3\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) + 3\( \sqrt{5} \)
45\( \sqrt{5} \) + 3\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
45\( \sqrt{5} \) + 3\( \sqrt{5} \)8 members of a bridal party need transported to a wedding reception but there are only 2 2-passenger taxis available to take them. How many will need to find other transportation?
| 7 | |
| 1 | |
| 4 | |
| 8 |
There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 8 people needing transportation leaving 8 - 4 = 4 who will have to find other transportation.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
|
distributive property for division |
|
distributive property for multiplication |
|
commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
A triathlon course includes a 100m swim, a 30.9km bike ride, and a 11.600000000000001km run. What is the total length of the race course?
| 52.5km | |
| 42.6km | |
| 51.7km | |
| 60.6km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 30.9km + 11.600000000000001km
total distance = 42.6km
A circular logo is enlarged to fit the lid of a jar. The new diameter is 65% larger than the original. By what percentage has the area of the logo increased?
| 30% | |
| 35% | |
| 22\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 65% the radius (and, consequently, the total area) increases by \( \frac{65\text{%}}{2} \) = 32\(\frac{1}{2}\)%