ASVAB Arithmetic Reasoning Practice Test 83223 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.28
Score	0%	66%

Review

What is $ \frac{6\sqrt{24}}{2\sqrt{6}} $?

71% Answer Correctly

	$\frac{1}{3}$ $ \sqrt{\frac{1}{4}} $
	$\frac{1}{4}$ $ \sqrt{\frac{1}{3}} $
	3 $ \sqrt{\frac{1}{4}} $
	3 $ \sqrt{4} $

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

$ \frac{6\sqrt{24}}{2\sqrt{6}} $
$ \frac{6}{2} $ $ \sqrt{\frac{24}{6}} $
3 $ \sqrt{4} $

Convert 6,192,000 to scientific notation.

62% Answer Correctly

	6.192 x 10⁵
	6.192 x 10⁶
	6.192 x 10^-6
	6.192 x 10^-5

Solution

A number in scientific notation has the format 0.000 x 10^exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

6,192,000 in scientific notation is 6.192 x 10⁶

How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?

52% Answer Correctly

	4
	6
	8
	3

Solution

To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:

cans = $ \frac{8 \text{ gallons}}{2 \text{ gallons}} $ = 4

Frank loaned Jennifer $1,000 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$1,060
	$1,080
	$1,040
	$1,070

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $1,000
i = 0.08 x $1,000

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,000 + $80
total = $1,080

Monty loaned Alex $200 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly

	$84
	$35
	$14
	$8

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $200
i = 0.07 x $200
i = $14

	\(\frac{1}{3}\) \( \sqrt{\frac{1}{4}} \)
	\(\frac{1}{4}\) \( \sqrt{\frac{1}{3}} \)
	3 \( \sqrt{\frac{1}{4}} \)
	3 \( \sqrt{4} \)