| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
Solve 3 + (3 + 3) ÷ 2 x 5 - 32
| \(\frac{8}{9}\) | |
| 1\(\frac{1}{3}\) | |
| 9 | |
| \(\frac{3}{4}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (3 + 3) ÷ 2 x 5 - 32
P: 3 + (6) ÷ 2 x 5 - 32
E: 3 + 6 ÷ 2 x 5 - 9
MD: 3 + \( \frac{6}{2} \) x 5 - 9
MD: 3 + \( \frac{30}{2} \) - 9
AS: \( \frac{6}{2} \) + \( \frac{30}{2} \) - 9
AS: \( \frac{36}{2} \) - 9
AS: \( \frac{36 - 18}{2} \)
\( \frac{18}{2} \)
9
Which of these numbers is a factor of 36?
| 10 | |
| 2 | |
| 18 | |
| 17 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.
What is \( \sqrt{\frac{9}{81}} \)?
| \(\frac{1}{3}\) | |
| 1\(\frac{2}{7}\) | |
| 1\(\frac{1}{7}\) | |
| \(\frac{8}{9}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{81}} \)
\( \frac{\sqrt{9}}{\sqrt{81}} \)
\( \frac{\sqrt{3^2}}{\sqrt{9^2}} \)
\(\frac{1}{3}\)
What is \( \frac{-1z^6}{3z^3} \)?
| -\(\frac{1}{3}\)z2 | |
| -\(\frac{1}{3}\)z3 | |
| -\(\frac{1}{3}\)z18 | |
| -3z-3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-z^6}{3z^3} \)
\( \frac{-1}{3} \) z(6 - 3)
-\(\frac{1}{3}\)z3
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
|
mixed number |
|
fraction |
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integer |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.