| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.23 |
| Score | 0% | 65% |
A tiger in a zoo has consumed 60 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 120 pounds?
| 6 | |
| 1 | |
| 8 | |
| 5 |
If the tiger has consumed 60 pounds of food in 6 days that's \( \frac{60}{6} \) = 10 pounds of food per day. The tiger needs to consume 120 - 60 = 60 more pounds of food to reach 120 pounds total. At 10 pounds of food per day that's \( \frac{60}{10} \) = 6 more days.
Convert 4,360,000 to scientific notation.
| 4.36 x 10-6 | |
| 4.36 x 106 | |
| 4.36 x 10-5 | |
| 4.36 x 107 |
A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:
4,360,000 in scientific notation is 4.36 x 106
If a car travels 250 miles in 5 hours, what is the average speed?
| 50 mph | |
| 40 mph | |
| 15 mph | |
| 75 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)What is the greatest common factor of 44 and 52?
| 13 | |
| 4 | |
| 7 | |
| 40 |
The factors of 44 are [1, 2, 4, 11, 22, 44] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 the greatest factor 44 and 52 have in common.
Cooks are needed to prepare for a large party. Each cook can bake either 5 large cakes or 12 small cakes per hour. The kitchen is available for 2 hours and 34 large cakes and 170 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 6 | |
| 8 | |
| 12 | |
| 11 |
If a single cook can bake 5 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 5 x 2 = 10 large cakes during that time. 34 large cakes are needed for the party so \( \frac{34}{10} \) = 3\(\frac{2}{5}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 12 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 12 x 2 = 24 small cakes during that time. 170 small cakes are needed for the party so \( \frac{170}{24} \) = 7\(\frac{1}{12}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 4 + 8 = 12 cooks.