| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
Solve 2 + (4 + 3) ÷ 2 x 3 - 42
| -3\(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| \(\frac{1}{2}\) | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (4 + 3) ÷ 2 x 3 - 42
P: 2 + (7) ÷ 2 x 3 - 42
E: 2 + 7 ÷ 2 x 3 - 16
MD: 2 + \( \frac{7}{2} \) x 3 - 16
MD: 2 + \( \frac{21}{2} \) - 16
AS: \( \frac{4}{2} \) + \( \frac{21}{2} \) - 16
AS: \( \frac{25}{2} \) - 16
AS: \( \frac{25 - 32}{2} \)
\( \frac{-7}{2} \)
-3\(\frac{1}{2}\)
What is \( \frac{2z^9}{6z^3} \)?
| \(\frac{1}{3}\)z6 | |
| 3z12 | |
| \(\frac{1}{3}\)z3 | |
| \(\frac{1}{3}\)z\(\frac{1}{3}\) |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{2z^9}{6z^3} \)
\( \frac{2}{6} \) z(9 - 3)
\(\frac{1}{3}\)z6
Simplify \( \frac{28}{64} \).
| \( \frac{6}{13} \) | |
| \( \frac{1}{4} \) | |
| \( \frac{7}{16} \) | |
| \( \frac{1}{2} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{64} \) = \( \frac{\frac{28}{4}}{\frac{64}{4}} \) = \( \frac{7}{16} \)
What is the distance in miles of a trip that takes 1 hour at an average speed of 50 miles per hour?
| 220 miles | |
| 50 miles | |
| 585 miles | |
| 420 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 50mph \times 1h \)
50 miles
Simplify \( \sqrt{32} \)
| 6\( \sqrt{2} \) | |
| 6\( \sqrt{4} \) | |
| 4\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{32} \)
\( \sqrt{16 \times 2} \)
\( \sqrt{4^2 \times 2} \)
4\( \sqrt{2} \)