ASVAB Arithmetic Reasoning Practice Test 838412 Results

Your Results Global Average
Questions 5 5
Correct 0 2.94
Score 0% 59%

Review

1

What is the greatest common factor of 16 and 28?

77% Answer Correctly
5
15
4
7

Solution

The factors of 16 are [1, 2, 4, 8, 16] and the factors of 28 are [1, 2, 4, 7, 14, 28]. They share 3 factors [1, 2, 4] making 4 the greatest factor 16 and 28 have in common.


2

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

least common multiple

greatest common factor

least common factor

absolute value


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


3

On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
59
37
43
33

Solution
If the guard hits 55% of his shots and takes 25 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{55}{100} \) = \( \frac{55 x 25}{100} \) = \( \frac{1375}{100} \) = 13 shots

The center makes 35% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{13}{\frac{35}{100}} \) = 13 x \( \frac{100}{35} \) = \( \frac{13 x 100}{35} \) = \( \frac{1300}{35} \) = 37 shots

to make the same number of shots as the guard and thus score the same number of points.


4

What is \( \sqrt{\frac{64}{4}} \)?

70% Answer Correctly
\(\frac{3}{4}\)
2\(\frac{1}{3}\)
1\(\frac{1}{7}\)
4

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{64}{4}} \)
\( \frac{\sqrt{64}}{\sqrt{4}} \)
\( \frac{\sqrt{8^2}}{\sqrt{2^2}} \)
\( \frac{8}{2} \)
4


5

If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?

47% Answer Correctly
50 m2
128 m2
2 m2
8 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.

Putting these two equations together and solving for width (w):

2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2

Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2