| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
6 members of a bridal party need transported to a wedding reception but there are only 2 2-passenger taxis available to take them. How many will need to find other transportation?
| 4 | |
| 3 | |
| 7 | |
| 2 |
There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 6 people needing transportation leaving 6 - 4 = 2 who will have to find other transportation.
What is 8a7 x 6a4?
| 48a11 | |
| 48a3 | |
| 14a7 | |
| 48a-3 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
8a7 x 6a4
(8 x 6)a(7 + 4)
48a11
If all of a roofing company's 8 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 16 | |
| 7 | |
| 8 | |
| 12 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 2 crews so there are \( \frac{8}{2} \) = 4 workers on a crew. 6 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 6 x 4 = 24 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 24 - 8 = 16 new staff for the busy season.
Charlie loaned Christine $1,400 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,442 | |
| $1,498 | |
| $1,512 | |
| $1,470 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.08 x $1,400
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,400 + $112What is \( 4 \)\( \sqrt{28} \) + \( 4 \)\( \sqrt{7} \)
| 8\( \sqrt{196} \) | |
| 8\( \sqrt{7} \) | |
| 12\( \sqrt{7} \) | |
| 16\( \sqrt{7} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{28} \) + 4\( \sqrt{7} \)
4\( \sqrt{4 \times 7} \) + 4\( \sqrt{7} \)
4\( \sqrt{2^2 \times 7} \) + 4\( \sqrt{7} \)
(4)(2)\( \sqrt{7} \) + 4\( \sqrt{7} \)
8\( \sqrt{7} \) + 4\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
8\( \sqrt{7} \) + 4\( \sqrt{7} \)