ASVAB Arithmetic Reasoning Practice Test 842581 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

A bread recipe calls for 1\(\frac{7}{8}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?

62% Answer Correctly
\(\frac{5}{8}\) cups
1\(\frac{1}{8}\) cups
2\(\frac{7}{8}\) cups
2 cups

Solution

The amount of flour you need is (1\(\frac{7}{8}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{15}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{5}{8} \) cups
\(\frac{5}{8}\) cups


2

What is \( \frac{4}{9} \) ÷ \( \frac{3}{7} \)?

68% Answer Correctly
\(\frac{1}{63}\)
\(\frac{16}{45}\)
1\(\frac{1}{27}\)
\(\frac{2}{45}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{9} \) ÷ \( \frac{3}{7} \) = \( \frac{4}{9} \) x \( \frac{7}{3} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{7}{3} \) = \( \frac{4 x 7}{9 x 3} \) = \( \frac{28}{27} \) = 1\(\frac{1}{27}\)


3

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

greatest common factor

least common factor

least common multiple


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


4

How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 6 gallon tank to fill it exactly halfway?

52% Answer Correctly
7
2
4
9

Solution

To fill a 6 gallon tank exactly halfway you'll need 3 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{3 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 2


5

Roger loaned Damon $1,500 at an annual interest rate of 8%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$4
$20
$32
$120

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,500
i = 0.08 x $1,500
i = $120