| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
A tiger in a zoo has consumed 56 pounds of food in 7 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 112 pounds?
| 13 | |
| 7 | |
| 6 | |
| 5 |
If the tiger has consumed 56 pounds of food in 7 days that's \( \frac{56}{7} \) = 8 pounds of food per day. The tiger needs to consume 112 - 56 = 56 more pounds of food to reach 112 pounds total. At 8 pounds of food per day that's \( \frac{56}{8} \) = 7 more days.
If a rectangle is twice as long as it is wide and has a perimeter of 6 meters, what is the area of the rectangle?
| 72 m2 | |
| 8 m2 | |
| 2 m2 | |
| 18 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 6 meters so the equation becomes: 2w + 2h = 6.
Putting these two equations together and solving for width (w):
2w + 2h = 6
w + h = \( \frac{6}{2} \)
w + h = 3
w = 3 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 3 - 2w
3w = 3
w = \( \frac{3}{3} \)
w = 1
Since h = 2w that makes h = (2 x 1) = 2 and the area = h x w = 1 x 2 = 2 m2
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 10% off." If Bob buys two shirts, each with a regular price of $27, how much money will he save?
| $5.40 | |
| $6.75 | |
| $2.70 | |
| $4.05 |
By buying two shirts, Bob will save $27 x \( \frac{10}{100} \) = \( \frac{$27 x 10}{100} \) = \( \frac{$270}{100} \) = $2.70 on the second shirt.
Which of the following is not an integer?
-1 |
|
\({1 \over 2}\) |
|
1 |
|
0 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
If \( \left|c - 1\right| \) + 9 = 4, which of these is a possible value for c?
| 3 | |
| 6 | |
| 2 | |
| -3 |
First, solve for \( \left|c - 1\right| \):
\( \left|c - 1\right| \) + 9 = 4
\( \left|c - 1\right| \) = 4 - 9
\( \left|c - 1\right| \) = -5
The value inside the absolute value brackets can be either positive or negative so (c - 1) must equal - 5 or --5 for \( \left|c - 1\right| \) to equal -5:
| c - 1 = -5 c = -5 + 1 c = -4 | c - 1 = 5 c = 5 + 1 c = 6 |
So, c = 6 or c = -4.