| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.57 |
| Score | 0% | 51% |
Solve 5 + (5 + 2) ÷ 3 x 2 - 42
| -6\(\frac{1}{3}\) | |
| 2 | |
| \(\frac{4}{7}\) | |
| \(\frac{2}{3}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (5 + 2) ÷ 3 x 2 - 42
P: 5 + (7) ÷ 3 x 2 - 42
E: 5 + 7 ÷ 3 x 2 - 16
MD: 5 + \( \frac{7}{3} \) x 2 - 16
MD: 5 + \( \frac{14}{3} \) - 16
AS: \( \frac{15}{3} \) + \( \frac{14}{3} \) - 16
AS: \( \frac{29}{3} \) - 16
AS: \( \frac{29 - 48}{3} \)
\( \frac{-19}{3} \)
-6\(\frac{1}{3}\)
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 12 gallon tank to fill it exactly halfway?
| 8 | |
| 4 | |
| 7 | |
| 4 |
To fill a 12 gallon tank exactly halfway you'll need 6 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{6 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 4
On average, the center for a basketball team hits 45% of his shots while a guard on the same team hits 65% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 29 | |
| 62 | |
| 26 | |
| 43 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{65}{100} \) = \( \frac{65 x 20}{100} \) = \( \frac{1300}{100} \) = 13 shots
The center makes 45% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{13}{\frac{45}{100}} \) = 13 x \( \frac{100}{45} \) = \( \frac{13 x 100}{45} \) = \( \frac{1300}{45} \) = 29 shots
to make the same number of shots as the guard and thus score the same number of points.
If there were a total of 250 raffle tickets sold and you bought 20 tickets, what's the probability that you'll win the raffle?
| 8% | |
| 1% | |
| 2% | |
| 7% |
You have 20 out of the total of 250 raffle tickets sold so you have a (\( \frac{20}{250} \)) x 100 = \( \frac{20 \times 100}{250} \) = \( \frac{2000}{250} \) = 8% chance to win the raffle.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 40% larger than the original. By what percentage has the area of the logo increased?
| 35% | |
| 27\(\frac{1}{2}\)% | |
| 30% | |
| 20% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 40% the radius (and, consequently, the total area) increases by \( \frac{40\text{%}}{2} \) = 20%