| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
What is \( 9 \)\( \sqrt{50} \) + \( 7 \)\( \sqrt{2} \)
| 16\( \sqrt{100} \) | |
| 63\( \sqrt{2} \) | |
| 52\( \sqrt{2} \) | |
| 63\( \sqrt{50} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{50} \) + 7\( \sqrt{2} \)
9\( \sqrt{25 \times 2} \) + 7\( \sqrt{2} \)
9\( \sqrt{5^2 \times 2} \) + 7\( \sqrt{2} \)
(9)(5)\( \sqrt{2} \) + 7\( \sqrt{2} \)
45\( \sqrt{2} \) + 7\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
45\( \sqrt{2} \) + 7\( \sqrt{2} \)14 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 5 | |
| 2 | |
| 4 | |
| 9 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 14 people needing transportation leaving 14 - 12 = 2 who will have to find other transportation.
A tiger in a zoo has consumed 30 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 54 pounds?
| 6 | |
| 4 | |
| 2 | |
| 1 |
If the tiger has consumed 30 pounds of food in 5 days that's \( \frac{30}{5} \) = 6 pounds of food per day. The tiger needs to consume 54 - 30 = 24 more pounds of food to reach 54 pounds total. At 6 pounds of food per day that's \( \frac{24}{6} \) = 4 more days.
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 49 | |
| 46 | |
| 43 | |
| 55 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46
How many hours does it take a car to travel 245 miles at an average speed of 35 miles per hour?
| 6 hours | |
| 9 hours | |
| 1 hour | |
| 7 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{245mi}{35mph} \)
7 hours