| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
On average, the center for a basketball team hits 25% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 23 | |
| 44 | |
| 31 | |
| 21 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{45}{100} \) = \( \frac{45 x 25}{100} \) = \( \frac{1125}{100} \) = 11 shots
The center makes 25% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{11}{\frac{25}{100}} \) = 11 x \( \frac{100}{25} \) = \( \frac{11 x 100}{25} \) = \( \frac{1100}{25} \) = 44 shots
to make the same number of shots as the guard and thus score the same number of points.
What is \( \frac{-5x^9}{6x^2} \)?
| -\(\frac{5}{6}\)x7 | |
| -\(\frac{5}{6}\)x11 | |
| -1\(\frac{1}{5}\)x7 | |
| -\(\frac{5}{6}\)x-7 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-5x^9}{6x^2} \)
\( \frac{-5}{6} \) x(9 - 2)
-\(\frac{5}{6}\)x7
A circular logo is enlarged to fit the lid of a jar. The new diameter is 70% larger than the original. By what percentage has the area of the logo increased?
| 22\(\frac{1}{2}\)% | |
| 15% | |
| 35% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 70% the radius (and, consequently, the total area) increases by \( \frac{70\text{%}}{2} \) = 35%
What is b2 + 4b2?
| -3b2 | |
| 5b-4 | |
| 3b2 | |
| 5b2 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
1b2 + 4b2
(1 + 4)b2
5b2
What is \( \frac{2}{5} \) x \( \frac{2}{6} \)?
| \(\frac{1}{15}\) | |
| \(\frac{2}{15}\) | |
| \(\frac{8}{81}\) | |
| \(\frac{4}{5}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{5} \) x \( \frac{2}{6} \) = \( \frac{2 x 2}{5 x 6} \) = \( \frac{4}{30} \) = \(\frac{2}{15}\)