| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.62 |
| Score | 0% | 72% |
If \( \left|z + 4\right| \) + 4 = -5, which of these is a possible value for z?
| 5 | |
| 6 | |
| -6 | |
| -2 |
First, solve for \( \left|z + 4\right| \):
\( \left|z + 4\right| \) + 4 = -5
\( \left|z + 4\right| \) = -5 - 4
\( \left|z + 4\right| \) = -9
The value inside the absolute value brackets can be either positive or negative so (z + 4) must equal - 9 or --9 for \( \left|z + 4\right| \) to equal -9:
| z + 4 = -9 z = -9 - 4 z = -13 | z + 4 = 9 z = 9 - 4 z = 5 |
So, z = 5 or z = -13.
What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?
| 40 | |
| 28 | |
| 31 | |
| 36 |
The equation for this sequence is:
an = an-1 + 7
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 7
a6 = 29 + 7
a6 = 36
What is -3c6 x 6c4?
| 3c6 | |
| 3c4 | |
| -18c10 | |
| -18c2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-3c6 x 6c4
(-3 x 6)c(6 + 4)
-18c10
A factor is a positive __________ that divides evenly into a given number.
integer |
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mixed number |
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fraction |
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improper fraction |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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distributive property for division |
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commutative property for division |
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commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).