ASVAB Arithmetic Reasoning Practice Test 853431 Results

Your Results Global Average
Questions 5 5
Correct 0 3.62
Score 0% 72%

Review

1

If \( \left|z + 4\right| \) + 4 = -5, which of these is a possible value for z?

62% Answer Correctly
5
6
-6
-2

Solution

First, solve for \( \left|z + 4\right| \):

\( \left|z + 4\right| \) + 4 = -5
\( \left|z + 4\right| \) = -5 - 4
\( \left|z + 4\right| \) = -9

The value inside the absolute value brackets can be either positive or negative so (z + 4) must equal - 9 or --9 for \( \left|z + 4\right| \) to equal -9:

z + 4 = -9
z = -9 - 4
z = -13
z + 4 = 9
z = 9 - 4
z = 5

So, z = 5 or z = -13.


2

What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?

92% Answer Correctly
40
28
31
36

Solution

The equation for this sequence is:

an = an-1 + 7

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 7
a6 = 29 + 7
a6 = 36


3

What is -3c6 x 6c4?

75% Answer Correctly
3c6
3c4
-18c10
-18c2

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-3c6 x 6c4
(-3 x 6)c(6 + 4)
-18c10


4

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

integer

mixed number

fraction

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for multiplication

distributive property for division

commutative property for division

commutative property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).