ASVAB Arithmetic Reasoning Practice Test 854788 Results

Your Results Global Average
Questions 5 5
Correct 0 2.50
Score 0% 50%

Review

1

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 25 gallon tank to fill it exactly halfway?

52% Answer Correctly
5
2
3
9

Solution

To fill a 25 gallon tank exactly halfway you'll need 12\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{12\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 5


2

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = b

b0 = 1

all of these are false

b1 = 1


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


3

A machine in a factory has an error rate of 7 parts per 100. The machine normally runs 24 hours a day and produces 7 parts per hour. Yesterday the machine was shut down for 9 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
104.9
157.9
97.6
125.4

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{7}{100} \) x 7 = \( \frac{7 \times 7}{100} \) = \( \frac{49}{100} \) = 0.49 errors per hour

So, in an average hour, the machine will produce 7 - 0.49 = 6.51 error free parts.

The machine ran for 24 - 9 = 15 hours yesterday so you would expect that 15 x 6.51 = 97.6 error free parts were produced yesterday.


4

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

69% Answer Correctly
23
38
28
31

Solution

The equation for this sequence is:

an = an-1 + 2(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31


5

What is \( 7 \)\( \sqrt{63} \) + \( 6 \)\( \sqrt{7} \)

35% Answer Correctly
27\( \sqrt{7} \)
42\( \sqrt{63} \)
13\( \sqrt{7} \)
13\( \sqrt{9} \)

Solution

To add these radicals together their radicands must be the same:

7\( \sqrt{63} \) + 6\( \sqrt{7} \)
7\( \sqrt{9 \times 7} \) + 6\( \sqrt{7} \)
7\( \sqrt{3^2 \times 7} \) + 6\( \sqrt{7} \)
(7)(3)\( \sqrt{7} \) + 6\( \sqrt{7} \)
21\( \sqrt{7} \) + 6\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

21\( \sqrt{7} \) + 6\( \sqrt{7} \)
(21 + 6)\( \sqrt{7} \)
27\( \sqrt{7} \)