| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.50 |
| Score | 0% | 50% |
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 25 gallon tank to fill it exactly halfway?
| 5 | |
| 2 | |
| 3 | |
| 9 |
To fill a 25 gallon tank exactly halfway you'll need 12\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{12\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 5
Which of the following statements about exponents is false?
b1 = b |
|
b0 = 1 |
|
all of these are false |
|
b1 = 1 |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
A machine in a factory has an error rate of 7 parts per 100. The machine normally runs 24 hours a day and produces 7 parts per hour. Yesterday the machine was shut down for 9 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 104.9 | |
| 157.9 | |
| 97.6 | |
| 125.4 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{7}{100} \) x 7 = \( \frac{7 \times 7}{100} \) = \( \frac{49}{100} \) = 0.49 errors per hour
So, in an average hour, the machine will produce 7 - 0.49 = 6.51 error free parts.
The machine ran for 24 - 9 = 15 hours yesterday so you would expect that 15 x 6.51 = 97.6 error free parts were produced yesterday.
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 23 | |
| 38 | |
| 28 | |
| 31 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
What is \( 7 \)\( \sqrt{63} \) + \( 6 \)\( \sqrt{7} \)
| 27\( \sqrt{7} \) | |
| 42\( \sqrt{63} \) | |
| 13\( \sqrt{7} \) | |
| 13\( \sqrt{9} \) |
To add these radicals together their radicands must be the same:
7\( \sqrt{63} \) + 6\( \sqrt{7} \)
7\( \sqrt{9 \times 7} \) + 6\( \sqrt{7} \)
7\( \sqrt{3^2 \times 7} \) + 6\( \sqrt{7} \)
(7)(3)\( \sqrt{7} \) + 6\( \sqrt{7} \)
21\( \sqrt{7} \) + 6\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
21\( \sqrt{7} \) + 6\( \sqrt{7} \)