| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.42 |
| Score | 0% | 68% |
In a class of 28 students, 10 are taking German and 12 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?
| 11 | |
| 9 | |
| 13 | |
| 20 |
The number of students taking German or Spanish is 10 + 12 = 22. Of that group of 22, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 22 - 3 = 19 who are taking at least one language. 28 - 19 = 9 students who are not taking either language.
If there were a total of 400 raffle tickets sold and you bought 16 tickets, what's the probability that you'll win the raffle?
| 12% | |
| 8% | |
| 4% | |
| 10% |
You have 16 out of the total of 400 raffle tickets sold so you have a (\( \frac{16}{400} \)) x 100 = \( \frac{16 \times 100}{400} \) = \( \frac{1600}{400} \) = 4% chance to win the raffle.
Which of the following is a mixed number?
\(1 {2 \over 5} \) |
|
\({a \over 5} \) |
|
\({7 \over 5} \) |
|
\({5 \over 7} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Which of the following is not an integer?
\({1 \over 2}\) |
|
-1 |
|
0 |
|
1 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 5 | |
| 6 | |
| 19 | |
| 4 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 7 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 7 x 3 = 21 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 21 - 15 = 6 new staff for the busy season.