ASVAB Arithmetic Reasoning Practice Test 857793 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

Which of the following is a mixed number?

83% Answer Correctly

\({5 \over 7} \)

\({a \over 5} \)

\(1 {2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?

55% Answer Correctly
1
14
9
5

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 7 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 7 x 3 = 21 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 21 - 12 = 9 new staff for the busy season.


3

If the ratio of home fans to visiting fans in a crowd is 4:1 and all 39,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
31,200
34,400
33,000
40,833

Solution

A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:

39,000 fans x \( \frac{4}{5} \) = \( \frac{156000}{5} \) = 31,200 fans.


4

What is \( \frac{2}{6} \) + \( \frac{8}{14} \)?

60% Answer Correctly
\( \frac{5}{10} \)
1 \( \frac{8}{42} \)
1 \( \frac{5}{42} \)
\(\frac{19}{21}\)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 14 are [14, 28, 42, 56, 70, 84, 98]. The first few multiples they share are [42, 84] making 42 the smallest multiple 6 and 14 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 7}{6 x 7} \) + \( \frac{8 x 3}{14 x 3} \)

\( \frac{14}{42} \) + \( \frac{24}{42} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{14 + 24}{42} \) = \( \frac{38}{42} \) = \(\frac{19}{21}\)


5

Convert z-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{z^{-3}} \)
\( \frac{1}{z^3} \)
\( \frac{-1}{-3z^{3}} \)
\( \frac{3}{z} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.